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问题: 高分求Delphi下的MD5算法。
描述: 如题。
解决方案1: unit MD5Unit;
interface
uses sysutils,dialogs;
(*MD5加密单元
不可逆散列加密
所有字符串均加密为一个32字节的16进制字符串
*)
function MD5(sMessage:WideString) :WideString;
implementation
function MD5(sMessage:WideString):WideString;
function RotateLeft(lValue, iShiftBits:integer):integer;
begin
result := (lValue shl iShiftBits) or (lValue shr (32-iShiftBits));
end;
function AddUnsigned(lX,lY:integer):integer;
var
lX4,lY4,lX8,lY8,lResult:integer;
begin
lX8 := (lX and $80000000);
lY8 := (lY and $80000000);
lX4 := (lX and $40000000);
lY4 := (lY and $40000000);
lResult := (lX and $3FFFFFFF)+(lY and $3FFFFFFF);
if (lX4 and lY4) <> 0 then begin result := (lResult xor $80000000 xor lX8 xor lY8); Exit; end;
if (lX4 or lY4) <> 0 then
begin
if (lResult and $40000000) <>0 then
begin result := (lResult xor $C0000000 xor lX8 xor lY8); end
else
begin result := (lResult xor $40000000 xor lX8 xor lY8); end
end
else
begin result := (lResult xor lX8 xor lY8); end
end;
function F(x,y,z:integer):integer; begin result := (x and y) or (( not x) and z); end;
function G(x,y,z:integer):integer; begin result := (x and z) or (y and ( not z)); end;
function H(x,y,z:integer):integer; begin result := (x xor y xor z); end;
function I(x,y,z:integer):integer; begin result := (y xor (x or ( not z))); end;
function FF(a,b,c,d,x,s,ac:integer):integer;
begin
a := AddUnsigned(a, AddUnsigned(AddUnsigned(F(b, c, d), x), ac));
result := AddUnsigned(RotateLeft(a, s), b);
end;
function GG(a,b,c,d,x,s,ac:integer):integer;
begin
a := AddUnsigned(a, AddUnsigned(AddUnsigned(G(b, c, d), x), ac));
result := AddUnsigned(RotateLeft(a, s), b);
end;
function HH(a,b,c,d,x,s,ac:integer):integer;
begin
a := AddUnsigned(a, AddUnsigned(AddUnsigned(H(b, c, d), x), ac));
result := AddUnsigned(RotateLeft(a, s), b);
end;
function II(a,b,c,d,x,s,ac:integer):integer;
begin
a := AddUnsigned(a, AddUnsigned(AddUnsigned(I(b, c, d), x), ac));
result := AddUnsigned(RotateLeft(a, s), b);
end;
type IntArray = array of integer;
function ConvertToWordArray(sMessage:WideString):IntArray;
var lWordCount:integer;
var lMessageLength:integer;
var lNumberOfWords_temp1:integer;
var lNumberOfWords_temp2:integer;
var lNumberOfWords:integer;
var lWordArray:IntArray;
var lBytePosition:integer;
var lByteCount:integer;
begin
lMessageLength := length(sMessage);
lNumberOfWords_temp1:=lMessageLength + 8;
lNumberOfWords_temp2:=(lNumberOfWords_temp1-(lNumberOfWords_temp1 mod 64)) div 64;
lNumberOfWords := (lNumberOfWords_temp2+1)*16;
SetLength(lWordArray,lNumberOfWords);
lBytePosition := 0;
lByteCount := 0;
while ( lByteCount < lMessageLength ) do
begin
lWordCount := (lByteCount-(lByteCount mod 4)) div 4;
lBytePosition := (lByteCount mod 4)*8;
lWordArray[lWordCount] := (lWordArray[lWordCount] or (ord(sMessage[lByteCount+1]) shl lBytePosition));
inc(lByteCount);
end;
lWordCount := (lByteCount-(lByteCount mod 4)) div 4;
lBytePosition := (lByteCount mod 4)*8;
lWordArray[lWordCount] := lWordArray[lWordCount] or ($80 shl lBytePosition);
lWordArray[lNumberOfWords-2] := lMessageLength shl 3;
lWordArray[lNumberOfWords-1] := lMessageLength shr 29;
result := lWordArray;
end;
function WordToHex(lValue:integer):WideString;
var WordToHexValue,WordToHexValue_temp:WideString;
lByte,lCount:integer;
begin
Result := '';
for lCount := 0 to 3 do
begin
lByte := (lValue shr (lCount*8)) and 255;
result := result + IntToHex(lByte,2);
end;
end;
var x:IntArray;
var k,AA,BB,CC,DD,a,b,c,d:integer;
const S11:integer=7; S12:integer=12; S13:integer=17; S14:integer=22;
S21:integer=5; S22:integer=9 ; S23:integer=14; S24:integer=20;
S31:integer=4; S32:integer=11; S33:integer=16; S34:integer=23;
S41:integer=6; S42:integer=10; S43:integer=15; S44:integer=21;
begin
// Steps 1 and 2. Append padding bits and length and convert to words
x := ConvertToWordArray(sMessage);
// Step 3. Initialise
a := $67452301; b := $EFCDAB89; c := $98BADCFE; d := $10325476;
// Step 4. Process the message in 16-word blocks
k :=0 ;
while k< length(x) do
//for (k=0;k<>
begin
AA:=a; BB:=b; CC:=c; DD:=d;
a:=FF(a,b,c,d,x[k+0], S11,$D76AA478);
d:=FF(d,a,b,c,x[k+1], S12,$E8C7B756);
c:=FF(c,d,a,b,x[k+2], S13,$242070DB);
b:=FF(b,c,d,a,x[k+3], S14,$C1BDCEEE);
a:=FF(a,b,c,d,x[k+4], S11,$F57C0FAF);
d:=FF(d,a,b,c,x[k+5], S12,$4787C62A);
c:=FF(c,d,a,b,x[k+6], S13,$A8304613);
b:=FF(b,c,d,a,x[k+7], S14,$FD469501);
a:=FF(a,b,c,d,x[k+8], S11,$698098D8);
d:=FF(d,a,b,c,x[k+9], S12,$8B44F7AF);
c:=FF(c,d,a,b,x[k+10],S13,$FFFF5BB1);
b:=FF(b,c,d,a,x[k+11],S14,$895CD7BE);
a:=FF(a,b,c,d,x[k+12],S11,$6B901122);
d:=FF(d,a,b,c,x[k+13],S12,$FD987193);
c:=FF(c,d,a,b,x[k+14],S13,$A679438E);
b:=FF(b,c,d,a,x[k+15],S14,$49B40821);
a:=GG(a,b,c,d,x[k+1], S21,$F61E2562);
d:=GG(d,a,b,c,x[k+6], S22,$C040B340);
c:=GG(c,d,a,b,x[k+11],S23,$265E5A51);
b:=GG(b,c,d,a,x[k+0], S24,$E9B6C7AA);
a:=GG(a,b,c,d,x[k+5], S21,$D62F105D);
d:=GG(d,a,b,c,x[k+10],S22,$2441453);
c:=GG(c,d,a,b,x[k+15],S23,$D8A1E681);
b:=GG(b,c,d,a,x[k+4], S24,$E7D3FBC8);
a:=GG(a,b,c,d,x[k+9], S21,$21E1CDE6);
d:=GG(d,a,b,c,x[k+14],S22,$C33707D6);
c:=GG(c,d,a,b,x[k+3], S23,$F4D50D87);
b:=GG(b,c,d,a,x[k+8], S24,$455A14ED);
a:=GG(a,b,c,d,x[k+13],S21,$A9E3E905);
d:=GG(d,a,b,c,x[k+2], S22,$FCEFA3F8);
c:=GG(c,d,a,b,x[k+7], S23,$676F02D9);
b:=GG(b,c,d,a,x[k+12],S24,$8D2A4C8A);
a:=HH(a,b,c,d,x[k+5], S31,$FFFA3942);
d:=HH(d,a,b,c,x[k+8], S32,$8771F681);
c:=HH(c,d,a,b,x[k+11],S33,$6D9D6122);
b:=HH(b,c,d,a,x[k+14],S34,$FDE5380C);
a:=HH(a,b,c,d,x[k+1], S31,$A4BEEA44);
d:=HH(d,a,b,c,x[k+4], S32,$4BDECFA9);
c:=HH(c,d,a,b,x[k+7], S33,$F6BB4B60);
b:=HH(b,c,d,a,x[k+10],S34,$BEBFBC70);
a:=HH(a,b,c,d,x[k+13],S31,$289B7EC6);
d:=HH(d,a,b,c,x[k+0], S32,$EAA127FA);
c:=HH(c,d,a,b,x[k+3], S33,$D4EF3085);
b:=HH(b,c,d,a,x[k+6], S34,$4881D05);
a:=HH(a,b,c,d,x[k+9], S31,$D9D4D039);
d:=HH(d,a,b,c,x[k+12],S32,$E6DB99E5);
c:=HH(c,d,a,b,x[k+15],S33,$1FA27CF8);
b:=HH(b,c,d,a,x[k+2], S34,$C4AC5665);
a:=II(a,b,c,d,x[k+0], S41,$F4292244);
d:=II(d,a,b,c,x[k+7], S42,$432AFF97);
c:=II(c,d,a,b,x[k+14],S43,$AB9423A7);
b:=II(b,c,d,a,x[k+5], S44,$FC93A039);
a:=II(a,b,c,d,x[k+12],S41,$655B59C3);
d:=II(d,a,b,c,x[k+3], S42,$8F0CCC92);
c:=II(c,d,a,b,x[k+10],S43,$FFEFF47D);
b:=II(b,c,d,a,x[k+1], S44,$85845DD1);
a:=II(a,b,c,d,x[k+8], S41,$6FA87E4F);
d:=II(d,a,b,c,x[k+15],S42,$FE2CE6E0);
c:=II(c,d,a,b,x[k+6], S43,$A3014314);
b:=II(b,c,d,a,x[k+13],S44,$4E0811A1);
a:=II(a,b,c,d,x[k+4], S41,$F7537E82);
d:=II(d,a,b,c,x[k+11],S42,$BD3AF235);
c:=II(c,d,a,b,x[k+2], S43,$2AD7D2BB);
b:=II(b,c,d,a,x[k+9], S44,$EB86D391);
a:=AddUnsigned(a,AA); b:=AddUnsigned(b,BB); c:=AddUnsigned(c,CC); d:=AddUnsigned(d,DD);
inc (k,16);
end;
result := LowerCase(WordToHex(a)+WordToHex(b)+WordToHex(c)+WordToHex(d));
end;
end.
以上介绍了“ 高分求Delphi下的MD5算法。”的问题解答,希望对有需要的网友有所帮助。
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