NSJSONSerializaton没有返回结果

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问题：NSJSONSerializaton没有返回结果
描述:

用了很多方法的都没有返回结果
先看一下代码:

json文件：

{ "speakers" : 
  [
    {
    "name":"Value",
    "picture": "URL VALUE",
    "business":"VALUE",
    "desc":"VALUE",
    "twitter": "URL VALUE"
    }                   
    {
           ...

    }
  ]
}

开始在一个dictionary中保存speaker属性
这个包含一个数组，有一些name，business属性

objective代码：

NSString *URLStr = @"URLofMyJsonFile";

NSURLRequest *JSONRequest = [NSURLRequest requestWithURL:[NSURL URLWithString:[NSString stringWithString:URLStr ]]];

NSData *JSONData = [NSURLConnection sendSynchronousRequest:JSONRequest returningResponse:nil error:nil];

NSError *parsingError = nil;

NSDictionary *speakerDictionnary = [NSJSONSerialization JSONObjectWithData:JSONData options:0 error:&parsingError];

NSArray *speakersArray = [speakerDictionnary objectForKey:@"news"];

for (NSDictionary *oneSpeaker in speakersArray) {
    NSLog(@"The speakers's name is %@", [oneSpeaker objectForKey:@"name"]);
    NSLog(@"The speakers's business is %@", [oneSpeaker objectForKey:@"business"]);
    NSLog(@"The speakers's desc is %@", [oneSpeaker objectForKey:@"desc"]);
}

---

解决方案1:

既然json出错，你可以试试下面代码：

[NSURLConnection sendAsynchronousRequest:[NSURLRequest requestWithURL:[NSURL URLWithString:@"http://www.appios.fr/client/takeoff/app/script/jsonSpeaker.json"]] queue:[NSOperationQueue mainQueue] completionHandler:^(NSURLResponse *reponse,NSData *data,NSError *error){
        if (!error) {
            NSError *jsonError;
            id json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:&jsonError];
            NSArray *speakersList = [json objectForKey:@"speakers"];
            [speakersList enumerateObjectsUsingBlock:^(NSDictionary *dict,NSUInteger idx,BOOL *Stop){
                NSLog(@"Name : %@",[dict objectForKey:@"name"]);
            }];
        }

    } ];

解决方案2:

在dictionary之间需要逗号。

{ "speakers" : 
  [
    {
        "name":"Value",
        "picture": "URL VALUE",
        "business":"VALUE",
        "desc":"VALUE",
        "twitter": "URL VALUE"
    } <=== MISSING COMMA HERE       
    {
       ...
    }
  ]
}

以上介绍了“NSJSONSerializaton没有返回结果”的问题解答，希望对有需要的网友有所帮助。
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